# Clamped square plate under uniform pressure. The plate is thin (``h = a / 100``), so Kirchhoff--Love plate theory is the relevant comparison. Unlike a simply supported rectangle, the fully clamped plate has no short closed form. The reference here is therefore deliberately a *quoted* value, ``w_max = 0.00126 q a^4 / D``, not a computed result: Timoshenko and Woinowsky-Krieger, *Theory of Plates and Shells*, 2nd ed. (1959), Table 35 (p. 202), the clamped rectangular-plate table. The tolerance reflects its three-significant- figure coefficient. ```python """Clamped square plate under uniform pressure. The plate is thin (``h = a / 100``), so Kirchhoff--Love plate theory is the relevant comparison. Unlike a simply supported rectangle, the fully clamped plate has no short closed form. The reference here is therefore deliberately a *quoted* value, ``w_max = 0.00126 q a^4 / D``, not a computed result: Timoshenko and Woinowsky-Krieger, *Theory of Plates and Shells*, 2nd ed. (1959), Table 35 (p. 202), the clamped rectangular-plate table. The tolerance reflects its three-significant- figure coefficient. """ import pathlib import sys import csdl_alpha as csdl import numpy as np import hermit as hm sys.path.insert(0, str(pathlib.Path(__file__).parent)) from _geometry import rect_plate # noqa: E402 from _harness import Case, main, node_nearest # noqa: E402 A = B = 1.0 E, NU, H, Q0 = 1.0e7, 0.3, 0.01, 1.0e3 D = E * H**3 / (12.0 * (1.0 - NU**2)) REFERENCE = 0.00126 * Q0 * A**4 / D def solve_at(n): """Centre deflection on an ``n x n`` quad mesh.""" mesh = rect_plate(A, B, nx=n, ny=n, cell="quad") rec = csdl.Recorder(inline=True) rec.start() domain = hm.ShellDomain(mesh, element="CG2CG1") material = hm.isotropic(domain, E=E, nu=NU, thickness=H, density=1.0) edge = lambda x: (np.isclose(x[0], 0.0) | np.isclose(x[0], A) | np.isclose(x[1], 0.0) | np.isclose(x[1], B)) state = hm.solve(domain, material, hm.traction(domain, [0.0, 0.0, Q0]), hm.clamp(domain, where=edge)) u = hm.nodal_displacement(state).value.reshape(-1, 3) rec.stop() k, dist = node_nearest(domain, [A / 2, B / 2, 0.0]) if dist > 1e-9: print(f" (note: centre sample node is {dist:.2e} away at n={n})") return abs(u[k, 2]) CASE = Case( name="Clamped uniformly loaded square plate", quantity="centre transverse deflection", reference=REFERENCE, tolerance=0.01, citation="Timoshenko & Woinowsky-Krieger, Theory of Plates and Shells, 2nd ed. " "(1959), Table 35, p. 202: quoted 0.00126", levels=(8, 12, 16, 24), quick_level=24, solve=solve_at, notes="a/h=100; reference coefficient is quoted to three significant figures", ) if __name__ == "__main__": main(CASE) ```